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SandraASA
@SandraASA
July 2022
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Помогите пожалуйста решить тригонометрическое уравнение cos3x+cos^3x=2cosx.
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Бахит
4cos³x-3cosx+cos³x-2cosx=0
5cos³x-5cosx=0
5cosx(cos²x-1)=0
1) cosx=0, x=π/2+πk, k∈Z
2) cosx=1, x=2πk
3) cosx=-1, x=π+2kπ
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Answers & Comments
5cos³x-5cosx=0
5cosx(cos²x-1)=0
1) cosx=0, x=π/2+πk, k∈Z
2) cosx=1, x=2πk
3) cosx=-1, x=π+2kπ