Помогите, пожалуйста, решить уравнения. Created by krosh2702. algebra-ru

Помогите, пожалуйста, решить уравнения...

July 2022 1 4 Report

Помогите, пожалуйста, решить уравнения

Answers & Comments

michindjeva
$\sqrt[3]{24 + \sqrt{ {x}^{2} + 5 } } = 3\\ 24 + \sqrt{ {x}^{2} + 5} = 27 \\ \sqrt{x {}^{2} + 5} = 27 - 24 = 3 \\ {x}^{2} + 5 = 9 \\ {x}^{2} = 4 \\ x1 = 2 \\ x2 = - 2$
$\sqrt{11 - \sqrt[3]{ {x}^{2} + 7 } } = 3 \\ 11 - \sqrt[3]{ {x}^{2} + 7} = 9 \\ \sqrt[3]{ {x}^{2} + 7 } = 2 \\ {x }^{2} + 7 = 8 \\ {x}^{2} = 1 \\ x1 = 1 \\ x2 = - 1$
$5 - x - \sqrt{x + 7} = 0 \\ 5 - x = \sqrt{x + 7} \\ 25 - 10x + {x}^{2} = x + 7 \\ {x }^{2} - 11x + 18 = 0 \\ x1 = 9 \\ x2 = 2$
x1 не подходит. т. к х<=5

2 votes Thanks 1

Answers & Comments

3 + 81^0,75...

pomogite pozhalujsta reshit neravenstva 1 3h 5 gt 4 2 4 h h 2

2x3 10 ne soderzhashij x raspishite pozhalujsta razlozhenie

pomogite pozhalujsta reshit sistemu uravnenij srochno 2x2 3xy2y24 2x23y

pomogite pozhalujsta s resheniemb8c05102762deaf77287746f83f7703c 73490

pomogite pozhalujsta s reshenieme1b70142f47e30e24e63468617fcdac1 91575

cosx3sinx2 pomogite pozhalujsta s resheniem zhelatelno reshenie v foto

pomogite pozhalujsta s resheniem059e0aaac8c9872a5dffc5f8c62cf7bb 4289

pomogite pozhalujsta reshit uravneniyae0c3a02f49717d36f12a77dc6e3f750c 28746

pomogite pozhalujsta reshit sistemub4aa1ab64f67d750ec3d3128c85465b2 78011

рекомендуемые вопросы

Helpful Links

Helpful Social