Помогите, пожалуйста, решить задание. Created by sasham99. algebra-ru

Помогите, пожалуйста, решить задание...

sasham99 @sasham99

July 2022 1 9 Report

Помогите, пожалуйста, решить задание

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arsenlevadniy

Verified answer

$\frac{11x^2-27xy+8y^2}{3x^2-y^2}=2$

$3x^2-y^2\neq0; \ 3\frac{x^2}{y^2}-1\neq0; \ (\frac{x}{y})^2\neq\frac{1}{3}; \ \frac{x}{y}\neq+-\frac{1}{\sqrt{3}}$

$11x^2-27xy+8y^2=2(3x^2-y^2)$

$5x^2-27xy+10y^2=0$

$5(\frac{x}{y})^2-27\frac{x}{y}+10=0$

$\frac{x}{y}=t$

$5t^2-27t+10=0$

D=529,

t1=0,4; t2=5;

$\frac{x}{y}=0,4$ или $\frac{x}{y}=5$

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Verified answer

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pervye 2 uravneniya sdelala i poluchila feoh3 dalshe ne znayu kak delat

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