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arsenia99
@arsenia99
July 2022
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Помогите пожалуйста решить!!!
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dnepr1
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Надо использовать теорему синусов:
ВС = (АС*sin A) / sinB.
sin A = sin (90-В) = cosB = √(1-sin²B) = √(1-(2/√13)²) = √(1-(4/13) = √(9/13) = 3/√13.
Тогда ВС = 6*(3/√13) / (2/√13) = 3*3 = 9.
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Answers & Comments
Verified answer
Надо использовать теорему синусов:ВС = (АС*sin A) / sinB.
sin A = sin (90-В) = cosB = √(1-sin²B) = √(1-(2/√13)²) = √(1-(4/13) = √(9/13) = 3/√13.
Тогда ВС = 6*(3/√13) / (2/√13) = 3*3 = 9.