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Tg A = 20/21; AB = 58Теорема ПифагораAC² + BC² = AB²BC = √1600 = 40Ответ: BC = 40

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December 2021 1 7 Report

помогите, пожалуйста, решить!

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Tg A = 20/21; AB = 58

$tg A = \frac{BC}{AC} = \frac{20}{21} \\ \\ AC = \frac{21}{20} BC$
Теорема Пифагора
AC² + BC² = AB²
$( \frac{21}{20} BC)^2+BC^2 =58^2 \\ \\ \frac{441}{400} BC^2+BC^2 =58^2 \\ \\ \frac{841}{400} BC^2=3364 \\ \\ BC^2=3364* \frac{400}{841} =4*400=1600$
BC = √1600 = 40
Ответ: BC = 40

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