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Tatyanushka
@Tatyanushka
August 2022
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Помогите пожалуйста с алгеброй, очень нужно
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маслёнок95
6) 2^(7/3)=2^(3х)
7/3=3х
7=9х
х=7/9
7)(5/3)^(2х) * (3/5)^3(х-5)=5/3
(5/3)^(2х) * (5/3)^(-3(х-5))=5/3
(5/3)^(2х) * (5/3)^(15-3х) = 5/3
(5/3)^(2х+15-3х)=5/3
(5/3)^(15-х)=5/3
15-х=1
х=14
8)х²-2х=6-х
х²-2х-6+х=0
х²-х-6=0
Д=1² - 4*1*(-6)=1+24=25=5²
х1=(1-5)/2=-2
х2=(1+5)/2=3
9)2^(х/3)=2^((3х+2)/2)
х/3=(3х+3)/2
2х=9х+9
7х=-9
х=-9/7
10)2^(1-х²+2х)=2^(-6)
1-х²+2х+6=0
х²-2х-7=0
Д=2²-4*1*(-7)=4+28=32=(4√2)²
х1=(2-4√2)/2=1-2√2
х2=1+2√2
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Tatyanushka
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Answers & Comments
7/3=3х
7=9х
х=7/9
7)(5/3)^(2х) * (3/5)^3(х-5)=5/3
(5/3)^(2х) * (5/3)^(-3(х-5))=5/3
(5/3)^(2х) * (5/3)^(15-3х) = 5/3
(5/3)^(2х+15-3х)=5/3
(5/3)^(15-х)=5/3
15-х=1
х=14
8)х²-2х=6-х
х²-2х-6+х=0
х²-х-6=0
Д=1² - 4*1*(-6)=1+24=25=5²
х1=(1-5)/2=-2
х2=(1+5)/2=3
9)2^(х/3)=2^((3х+2)/2)
х/3=(3х+3)/2
2х=9х+9
7х=-9
х=-9/7
10)2^(1-х²+2х)=2^(-6)
1-х²+2х+6=0
х²-2х-7=0
Д=2²-4*1*(-7)=4+28=32=(4√2)²
х1=(2-4√2)/2=1-2√2
х2=1+2√2