Помогите, пожалуйста, упростить. Created by Sabiwka1410. algebra-ru

Помогите, пожалуйста, упростить...

Sabiwka1410 @Sabiwka1410

July 2022 1 10 Report

Помогите, пожалуйста, упростить

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Эксперт5

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$\frac{(2x^{1/2})^3y^2z^{3/4}}{4x^2y^{1/2}z^{3/2}} = \frac{8x^{3/2}y^{2-1/2}}{4x^2z^{3/2-3/4}}= \frac{2y^{3/2}}{x^{2-3/2}z^{3/4}}} =\\\\= \frac{2y^{3/2}}{x^{1/2}z^{3/4}}= \frac{2y^{1,5}}{x^{0,5}z^{0,75}}$

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