AB CD = 2 к 1
EF MN = 1 к 1
AC DF = 3 к 3 = 1 к 1
AN CE = 9 к 3 = 3 к 1
EN BM = 3 к 6 = 1 к 2
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AB CD = 2 к 1
EF MN = 1 к 1
AC DF = 3 к 3 = 1 к 1
AN CE = 9 к 3 = 3 к 1
EN BM = 3 к 6 = 1 к 2