Помогите пожалуйста... . Created by kott5. algebra-ru

Ответ: cosα=-0,6.Объяснение:sinα*tgα+5*sinα-3*tgα=15sinα*tgα+5*sinα-3*tgα-15=0sinα*(tgα+5)-3*(tgα+5)=0(tgα+5)*(sinα-3=0{tgα+5=0 {tgα=-5{sinα-3=0 {sinα=3cosα=sinα/tgα=3/(-5)=-3/5=-0,6. Помогите пожалуйста с решением. Очень срочно https://znanija.com/task/34599351?utm_source=android&utm_medium=share&utm_campaign=questionПомогите пожалуйста https://znanija.com/task/34606261?utm_source=android&utm_medium=share&utm_campaign=questionнет такого ответа..нет такого ответаНовые вопросы в Алгебрапомогите решить 15 и 16 задание!!!Найдите значение выражения помогите пжпжпжмжПомогите пожалуйста с 2 и 3Помогите пожалуйста с 4 и 6Разложите на множители числитель и знаменатель дробей и сократите ихпомогите пжпжппжпжжпПожалуйста срочно!!!!!! 1 вопрос найдите взаимосвязь в таблице1 вопрос найдите взаимосвязь в таблицеТурист відійшов від табору на 8 км і зупинився відпо чити. 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kott5 @kott5

July 2022 1 3 Report

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Answers & Comments

sangers1959

Verified answer

Ответ: cosα=-0,6.

Объяснение:

sinα*tgα+5*sinα-3*tgα=15

sinα*tgα+5*sinα-3*tgα-15=0

sinα*(tgα+5)-3*(tgα+5)=0

(tgα+5)*(sinα-3=0

{tgα+5=0 {tgα=-5

{sinα-3=0 {sinα=3

cosα=sinα/tgα=3/(-5)=-3/5=-0,6.

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