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September 2021
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oganesbagoyan
Verified answer
(x-1)(x-2)(x-3)
/
(x+1)(x+2)(x+3) > 1 ;
(x-1)(x-2)(x-3)
/
(x+1)(x+2)(x+3) -1 > 0;
(
(x-1)(x-2)(x-3) -(x+1)(x+2)(x+3)
)/
(x+1)(x+2)(x+3) > 0;
(
(x² -3x+2)(x-3) -(x²+3x+2)(x+3)
) /
(x+1)(x+2)(x+3) >0 ;
-12(x² +1)/(x+1)(x+2)(x+3) >0 ; * * * -12(x²+1) < 0 * * *
(x+1)(x+2)(x+3) <0 ; * * * (x+3)(x+2)(x+1)< 0 * * *
методом интервалов :
- + - +
----------- ( -3 )---------( -2) ----------(-1) -----------
x∈(-∞; - 3) U ( -2; -1) .
2 votes
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45289
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Answers & Comments
Verified answer
(x-1)(x-2)(x-3)/(x+1)(x+2)(x+3) > 1 ;(x-1)(x-2)(x-3)/(x+1)(x+2)(x+3) -1 > 0;
((x-1)(x-2)(x-3) -(x+1)(x+2)(x+3))/ (x+1)(x+2)(x+3) > 0;
( (x² -3x+2)(x-3) -(x²+3x+2)(x+3)) / (x+1)(x+2)(x+3) >0 ;
-12(x² +1)/(x+1)(x+2)(x+3) >0 ; * * * -12(x²+1) < 0 * * *
(x+1)(x+2)(x+3) <0 ; * * * (x+3)(x+2)(x+1)< 0 * * *
методом интервалов :
- + - +
----------- ( -3 )---------( -2) ----------(-1) -----------
x∈(-∞; - 3) U ( -2; -1) .