Ответ:
3а). =3√2-3√3/3√5=3(√2-√3)/3√5=√2-√3/√5
3б). = х-√3/(х-√3)(х+√3)=1/х+√3.
3в). = √х(√х-1)/2√х=√х-1/2
2б) =9с^3
2в) =0,5а^4b^-5
2а)= z^-7
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Ответ:
3а). =3√2-3√3/3√5=3(√2-√3)/3√5=√2-√3/√5
3б). = х-√3/(х-√3)(х+√3)=1/х+√3.
3в). = √х(√х-1)/2√х=√х-1/2
2б) =9с^3
2в) =0,5а^4b^-5
2а)= z^-7