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Sk5
@Sk5
July 2022
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sedinalana
Verified answer
(a^-2-a)/((√a)^-1-√a)=(1/a² -a):(1/√a -√a)=(1-a3)/a²:(1-a)/√a=
=(1-a)(1+a+a²)/a² *√a/(1-a)=(1+a+a²)/a√a
(a^-2 -1)/√a-√a^-1)=(1/a²-1):(√a)=(1-a²)/a²:(a+1)/√a=
=(1-a)(1+a)/a²*√a/(a+1)=(1-a)/a√a
получим
√a-(1+a+a²)/a√a-(1-a)/a√a +2/a√a=
=(a²-1-a-a²-1+a+2)/a√a=0/a√a=0
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Answers & Comments
Verified answer
(a^-2-a)/((√a)^-1-√a)=(1/a² -a):(1/√a -√a)=(1-a3)/a²:(1-a)/√a==(1-a)(1+a+a²)/a² *√a/(1-a)=(1+a+a²)/a√a
(a^-2 -1)/√a-√a^-1)=(1/a²-1):(√a)=(1-a²)/a²:(a+1)/√a=
=(1-a)(1+a)/a²*√a/(a+1)=(1-a)/a√a
получим
√a-(1+a+a²)/a√a-(1-a)/a√a +2/a√a=
=(a²-1-a-a²-1+a+2)/a√a=0/a√a=0