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synchron2005
@synchron2005
July 2022
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juli531
1) 4 в степени -4 (4^-4)
2)..= -1/(2^3 +4) + 3 = -1/12 +3 = 2 целых 11/12 = 35/12
3)...=(а-(1/а))*а/(а-1) -1=(а^2 -1)/а * а/(а-1) -1= (а^2 -1)/(а-1) -1= ((а-1)(а+1))/а-1 -1= а+1 -1 =а
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Answers & Comments
2)..= -1/(2^3 +4) + 3 = -1/12 +3 = 2 целых 11/12 = 35/12
3)...=(а-(1/а))*а/(а-1) -1=(а^2 -1)/а * а/(а-1) -1= (а^2 -1)/(а-1) -1= ((а-1)(а+1))/а-1 -1= а+1 -1 =а