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MrQelen
@MrQelen
July 2022
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помогите пожалуйста!!!
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sedinalana
1
3^x*(3-1)=18
3^x*2=18
3^x=9
x=2
2
log(4)x=t
t²+t-6=0
t1+t2=-1 U t1*t2=-6
t1=-3⇒log(4)x=-1⇒x=1/4
t2=2⇒log(4)x=2⇒x=16
3
log(3)x=3
x=27
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Answers & Comments
3^x*(3-1)=18
3^x*2=18
3^x=9
x=2
2
log(4)x=t
t²+t-6=0
t1+t2=-1 U t1*t2=-6
t1=-3⇒log(4)x=-1⇒x=1/4
t2=2⇒log(4)x=2⇒x=16
3
log(3)x=3
x=27