Помогите пж 14 баллов. Created by damoknurgali. algebra-ru

Помогите пж 14 баллов...

July 2022 2 9 Report

Помогите пж 14 баллов

vitalik201060

$\frac{Cos135^{o}Sin240^{o}Ctg210^{o}}{tg330^{o}}=\frac{Cos(90^{0}+45^{o})*Sin(270^{o}-30^{o})*Ctg(180^{o}+30^{o})}{tg(360^{o}-30^{o})}=\frac{-Sin45^{o}*(-Cos30^{o})*Ctg30^{o}}{-tg30^{o}}=-\frac{\frac{\sqrt{2}}{2}*\frac{\sqrt{3}}{2}*\sqrt{3}}{\frac{\sqrt{3}}{3}}=-\frac{3\sqrt{6}}{4}$

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Universalka

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Нужно было перевести в табличные углы и решить

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