помогите расписать по формуле двойного угла: tg 6 x=... cos8x=... tg 8 x=...
tg6x= 2tg3x / ( 1-tg^2 * 3x)
cos8x = cos^2 *4x- sin^2 4x
tg 8x - 2tg4x /( 1 - tg^2 4x)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
tg6x= 2tg3x / ( 1-tg^2 * 3x)
cos8x = cos^2 *4x- sin^2 4x
tg 8x - 2tg4x /( 1 - tg^2 4x)