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mona76
@mona76
August 2022
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Помогите решить 2 простых уравнения:
1) cos 3x = 0
2) 2 cosx - 1 = 0
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RecoveryV
1)cos3x=0
3x=П/2+Пn
x=П/6+Пn/3,n принадлежит Z.
2)
2cosx=1
cosx=1/2
x=+-pi/3+2pi.n
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Answers & Comments
3x=П/2+Пn
x=П/6+Пn/3,n принадлежит Z.
2)2cosx=1
cosx=1/2
x=+-pi/3+2pi.n