(2у - 3у²) = (2у) ² - 2 × 2у × 3у + (3у)²
2y - 3y² = 4у² - 12у² + 9у²
2y - 3y² = у²
-3у² - у² = 2y
-4у² = 2y
-4у² - 2y = 0
-2у (2y - 1) = 0
y (2y - 1) = 0
y = 0
или
2у - 1 = 0
2у = 1
у = 1/2
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(2у - 3у²) = (2у) ² - 2 × 2у × 3у + (3у)²
2y - 3y² = 4у² - 12у² + 9у²
2y - 3y² = у²
-3у² - у² = 2y
-4у² = 2y
-4у² - 2y = 0
-2у (2y - 1) = 0
y (2y - 1) = 0
y = 0
или
2у - 1 = 0
2у = 1
у = 1/2