Помогите решить
2x^4+x^3-6x^2+x+2=0
(x-1)^2*(x+2)*(2x+1)=0
(x-1)^2=0 или x+2=0 или 2x+1=0
x²-2x+1=0 x=-2 2x=-1
D=4-4=0 x=-1/2=-0.5
x=(2+0)/2
x=1
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2x^4+x^3-6x^2+x+2=0
(x-1)^2*(x+2)*(2x+1)=0
(x-1)^2=0 или x+2=0 или 2x+1=0
x²-2x+1=0 x=-2 2x=-1
D=4-4=0 x=-1/2=-0.5
x=(2+0)/2
x=1