Помогите решить 6,7 номера. Created by ferdas1. algebra-ru

Помогите решить 6,7 номера...

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Помогите решить 6,7 номера

dnepr1

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$6) ( \frac{c}{c-d} + \frac{c}{d} ): \frac{c}{2c^2-2d^2} =$
$= \frac{cd+c^2-cd}{d(c-d)} : \frac{c}{2(c-d)(c+d)} =$
= $\frac{c^2*2(c-d)(c+d)}{cd(c-d)} = \frac{2c(c+d)}{d} = \frac{2c^2}{d} +2c$
7) 2x-4-2(x+13) >=5x
2x-4-2x-26>=5x
5x<=-30
x<=-6
x max = -6.

1 votes Thanks 1

Dasha07200062 Корень 27 * корень 3=корень 81 ,а это есть (9)

(2корень3)^2-это есть = 4*3=12

9-12=-3

0 votes Thanks 0

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tex] -3...

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