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vishnevetckiy08
@vishnevetckiy08
July 2022
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Помогите решить домашку. Номер 1.25
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sedinalana
1.25
a+1/a=3
а)a²+1/a²=(a+1/a)²-2=3²-2=9-2=7
б)(a^4+1)/(2a²)=1/2*(a²+1/a²)=1/2*7=3,5
в)(a^8+1)/a^4=(a^4+1/a^4)=(a²+1/a²)²-2=19-2=47
г)a³+1/a³=(a+1/a)(a²+1/a²-1)=3*(7-1)=3*6=18
1 votes
Thanks 1
Fixytup
так ведь надо было решить только 1.25
sedinalana
сначала просили вообще все!
Fixytup
1 votes
Thanks 1
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Answers & Comments
a+1/a=3
а)a²+1/a²=(a+1/a)²-2=3²-2=9-2=7
б)(a^4+1)/(2a²)=1/2*(a²+1/a²)=1/2*7=3,5
в)(a^8+1)/a^4=(a^4+1/a^4)=(a²+1/a²)²-2=19-2=47
г)a³+1/a³=(a+1/a)(a²+1/a²-1)=3*(7-1)=3*6=18