Verified answer

㏒₁/₂㏒₃(x-46) ≥ -1                 ОДЗ х-46>0  x> 46

㏒₃(x-46) ≤ (1/2)⁻¹

㏒₃(x-46) ≤ 2

x-46 ≤ 3²

x≤ 9+46

x ≤  55

Ответ: х∈ (46; 55]

Verified answer

с) log₀.₅ log₃(x - 46) ≥ -1

ОДЗ: х > 46 и log₃(x - 46) > 0

log₀.₅ log₃(x - 46) ≥ -log₀.₅(0.5)

log₀.₅ log₃(x - 46) ≥ log₀.₅(0.5)⁻¹

log₀.₅ log₃(x - 46) ≥ log₀.₅2

log₃(x - 46) ≤ 2

log₃(x - 46) ≤ log₃9

x - 46 ≤ 9

x ≤ 46 + 9

x ≤ 55

Ответ: х ∈ (46; 55}