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Kayshka
@Kayshka
November 2021
1
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помогите решить очень срочно!
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oganesbagoyan
Verified answer
(4x² -23x +33)/(x-3) =x-3 ;* * *ОДЗ: x≠3 * * *
4(x-3)(x-11/4)/(x-3) = x-3 ;
4(x -11/4) = x -3 ;
4x -11 =x -3 ;
4x-x =11-3 ;
3x =8 ;
x =8/3. ∈ (2,6 ; 2;7) → 3 _вариант.
-------
√(5-x) /(x² -2x -3) * * * ООВ ? * * *
{ 5 -x ≥0 ; x² -2x -3 ≠0 .⇔ { x≤5 ; x ≠ -1 ; x ≠ 3 .
ответ: x∈(-∞ ;-1) U(-1; 3) U (3 ; 5].
* * * x² -2x -3 =0 ; D/4 =1² -(-3) =4 =2²; x₁=1-2 =
-1
; x₁=1+2 =
3
** *
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Kayshka
какой ответ во 2?
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Answers & Comments
Verified answer
(4x² -23x +33)/(x-3) =x-3 ;* * *ОДЗ: x≠3 * * *4(x-3)(x-11/4)/(x-3) = x-3 ;
4(x -11/4) = x -3 ;
4x -11 =x -3 ;
4x-x =11-3 ;
3x =8 ;
x =8/3. ∈ (2,6 ; 2;7) → 3 _вариант.
-------
√(5-x) /(x² -2x -3) * * * ООВ ? * * *
{ 5 -x ≥0 ; x² -2x -3 ≠0 .⇔ { x≤5 ; x ≠ -1 ; x ≠ 3 .
ответ: x∈(-∞ ;-1) U(-1; 3) U (3 ; 5].
* * * x² -2x -3 =0 ; D/4 =1² -(-3) =4 =2²; x₁=1-2 = -1 ; x₁=1+2 =3 ** *