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laura2016
@laura2016
July 2022
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Помогите решить, пожалуйста
|x^2+x-5| больше 3х
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sedinalana
Verified answer
X²+x-5<-3x U x²+x-5>3x
1)x²+x-5<-3x
x²+4x-5<0
x1+x2=-4 U x1*x2=-5
x1=-5 U x2=1
-5<x<1
2)x²+x-5>3x
x²-2x-5>0
D=4+20=24
x1=(2-2√6)/2=1-√6
x2=1+√6
x<1-√6 U x>1+√6
x∈(-∞;1) U (1+√6;∞)
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Answers & Comments
Verified answer
X²+x-5<-3x U x²+x-5>3x1)x²+x-5<-3x
x²+4x-5<0
x1+x2=-4 U x1*x2=-5
x1=-5 U x2=1
-5<x<1
2)x²+x-5>3x
x²-2x-5>0
D=4+20=24
x1=(2-2√6)/2=1-√6
x2=1+√6
x<1-√6 U x>1+√6
x∈(-∞;1) U (1+√6;∞)