Помогите решить, пожалуйста.. Created by DagyBagy. algebra-ru

Помогите решить, пожалуйста...

DagyBagy @DagyBagy

July 2022 1 2 Report

Помогите решить, пожалуйста.

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NNNLLL54

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$\int \frac{sint\, cost\, dt}{\sqrt{1+sin^2t}}=[\; u=1+sin^2t\; ,\; du=2sint\, cost\; dt\; ]=\frac{1}{2}\int \frac{du}{\sqrt{u}}=\\\\=\frac{1}{2}\cdot 2\sqrt{u}+C=\sqrt{1+sin^2t}+C$

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