nikitokkk
1) SiO2+3C=SiC+2CO n(SiC)=10000/40=250 моль m(SiO2)=250*60=15000 г m(песка)=15000/0.95=15800=15.8 кг m(C)=3*250*12=9000 г m(угля)=9000/0.98=9180 г=9.18 кг 2) CaCO3+H2SO4=CaSO4+H2O+CO2 n(CO2)=0.14/22,4=0.00625 m(CaCO3)=0.00625*100=0.625 г w(CaCO3)=0.625/0.75=0.83333=83.3 % w(примесей)=100-83.3=16.67 %
Answers & Comments
n(SiC)=10000/40=250 моль
m(SiO2)=250*60=15000 г
m(песка)=15000/0.95=15800=15.8 кг
m(C)=3*250*12=9000 г
m(угля)=9000/0.98=9180 г=9.18 кг
2) CaCO3+H2SO4=CaSO4+H2O+CO2
n(CO2)=0.14/22,4=0.00625
m(CaCO3)=0.00625*100=0.625 г
w(CaCO3)=0.625/0.75=0.83333=83.3 %
w(примесей)=100-83.3=16.67 %