Помогите решить, пример во вложения
(-16x^2+8x+3)/(-4x^2 -8x-3) <=0
-16x^2+8x+3 >=0
D=64+4*16*3 =V256=16
x=-8+16/-32 =8/-32=-1/4
x2=-24/ -32=3/4
-4x^2-8x-3<0
D=64-4*-4*-3=64-48=V16=4
x=8+4/-8=12 / -8= -3/2
x2=8-4/-8=-1/2
Ответ (-3/2 -1/2) U [-1/4 ; 3/4]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
(-16x^2+8x+3)/(-4x^2 -8x-3) <=0
-16x^2+8x+3 >=0
D=64+4*16*3 =V256=16
x=-8+16/-32 =8/-32=-1/4
x2=-24/ -32=3/4
-4x^2-8x-3<0
D=64-4*-4*-3=64-48=V16=4
x=8+4/-8=12 / -8= -3/2
x2=8-4/-8=-1/2
Ответ (-3/2 -1/2) U [-1/4 ; 3/4]