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thijs
@thijs
August 2022
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Помогите решить ( с объяснением) Даю 20 баллов
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армения20171
Verified answer
Sin(arctg(-1/4)-5π/2)=-sin(2π+π/2-arctg(-1/4)
=-cos(arctg(-1/4))
arctg(-1/4)=a€[-π/2;π/2]
tga=-1/4;а €[-π/2;0]
1+tg²a=1/cos²a
cos²a=1/(1+1/16)=16/17
cosa=4/√17
-cos(arctg(-1/4)=-4/√17=
-4√17/17
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Answers & Comments
Verified answer
Sin(arctg(-1/4)-5π/2)=-sin(2π+π/2-arctg(-1/4)=-cos(arctg(-1/4))
arctg(-1/4)=a€[-π/2;π/2]
tga=-1/4;а €[-π/2;0]
1+tg²a=1/cos²a
cos²a=1/(1+1/16)=16/17
cosa=4/√17
-cos(arctg(-1/4)=-4/√17=
-4√17/17