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missmarysya
@missmarysya
November 2021
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Корень(x^2-y^2) = z >= 0
корень(x-y) = t >= 0
z+t=6
z^2-t^2=12
**********
z+t=6
z-t=2
**********
z=4
t=2
**********
z=4=корень(x^2-y^2)
t=2=корень(x-y)
**********
(x^2-y^2)=16
(x-y)=4
**********
(x+y)=4
(x-y)=4
**********
x=4
y=0
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Answers & Comments
Verified answer
Корень(x^2-y^2) = z >= 0корень(x-y) = t >= 0
z+t=6
z^2-t^2=12
**********
z+t=6
z-t=2
**********
z=4
t=2
**********
z=4=корень(x^2-y^2)
t=2=корень(x-y)
**********
(x^2-y^2)=16
(x-y)=4
**********
(x+y)=4
(x-y)=4
**********
x=4
y=0