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PotatoKnight
@PotatoKnight
August 2022
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srzontmp
1) 11011011(2)=219(10) - вар 4
2) z = 16 = 10000(2) - вар 3
3) 1+6+32+64 - 7 цифр в двоичн
4) A2(16)+51(8) = 313(8) - вар 3
5) 1001(2) + 1106(8) + AC(16) = 1373(8) - посл циф 3
6) 25(8)=10101(2) 10(2)+10101(2) = 10111(2)
7) 51(10) = 201(x) -> 2i^2+1=51 -> i^2=25 -> i=5 - основание
8) 53(10) = 310(4) = 3*16+3*1+0=51(10)
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Answers & Comments
2) z = 16 = 10000(2) - вар 3
3) 1+6+32+64 - 7 цифр в двоичн
4) A2(16)+51(8) = 313(8) - вар 3
5) 1001(2) + 1106(8) + AC(16) = 1373(8) - посл циф 3
6) 25(8)=10101(2) 10(2)+10101(2) = 10111(2)
7) 51(10) = 201(x) -> 2i^2+1=51 -> i^2=25 -> i=5 - основание
8) 53(10) = 310(4) = 3*16+3*1+0=51(10)