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PotatoKnight
@PotatoKnight
August 2022
1
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рассчитайте массовую долю меди в оксидах CuO Cu2O
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dhyt
CuO:
w=m(в-ва)/m(р-ра) * 100%
M(CuO)=64+16=80г/моль
w=64/80 * 100%= 80%
Cu2O:
w=m(в-ва)/m(р-ра) * 100%
M(Cu2O)=64*2+16=144г/моль
w=64*2/144 * 100%=89%
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Answers & Comments
w=m(в-ва)/m(р-ра) * 100%
M(CuO)=64+16=80г/моль
w=64/80 * 100%= 80%
Cu2O:
w=m(в-ва)/m(р-ра) * 100%
M(Cu2O)=64*2+16=144г/моль
w=64*2/144 * 100%=89%