Home
О нас
Products
Services
Регистрация
Войти
Поиск
korolevka009
@korolevka009
August 2022
1
12
Report
помогите решить срочьно
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
rubilovalek
Verified answer
Формула суммы n членов геометрической прогрессии: S(n)= b(1)*(q^n-1)/(q-1). в нашем случае: b(1)=5, q=2, n=4. S(4)=5*(2^4-1)/(2-1)=5*(16-1)=5*15=75. Ответ: S(4)=75.
0 votes
Thanks 0
×
Report "помогите решить срочьно..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Формула суммы n членов геометрической прогрессии: S(n)= b(1)*(q^n-1)/(q-1). в нашем случае: b(1)=5, q=2, n=4. S(4)=5*(2^4-1)/(2-1)=5*(16-1)=5*15=75. Ответ: S(4)=75.