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korolevka009
@korolevka009
August 2022
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rubilovalek
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Формула суммы n членов геометрической прогрессии: S(n)= b(1)*(q^n-1)/(q-1). в нашем случае: b(1)=5, q=2, n=4. S(4)=5*(2^4-1)/(2-1)=5*(16-1)=5*15=75. Ответ: S(4)=75.
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Answers & Comments
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Формула суммы n членов геометрической прогрессии: S(n)= b(1)*(q^n-1)/(q-1). в нашем случае: b(1)=5, q=2, n=4. S(4)=5*(2^4-1)/(2-1)=5*(16-1)=5*15=75. Ответ: S(4)=75.