Verified answer

Вместо "у штрих" буду писать " y¹ ".

y¹=12*(x/3+2)¹¹*1/3=...

y¹=13*(15-9x)¹² *(-9)=...

y¹=cos(5-3x) *(5-3x)¹= -3*cos(5-3x)

y¹=-sin(9x-10) *(9x-10)¹=-9 *sin(9x-10)

y¹=-1/sin²(π/4-4x) *(π/4-4x)¹=+4*1/sin²(π/4-4x)

y¹=1/2* 1/√(4-9x) *(4-9x)¹=-9/2*1/(4-9x)