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varusha2000
@varusha2000
July 2022
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Помогите решить тригонометрическое уравнение: cos7x-cosx-sin4x=0
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mimimishka142
Cos7x-cosx=-sin4xsin3x
-sin4xsin3x-sin4x=0
-sin4x(sin3x+1)=0
sin4x=0 x=(π/4)n, n∈Z
sin3x=-1 x=-π/6+(2/3)πm, m∈z
1 votes
Thanks 2
varusha2000
как мы получили -sin4xsin3x? А так, спасибо за решение)
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Answers & Comments
-sin4xsin3x-sin4x=0
-sin4x(sin3x+1)=0
sin4x=0 x=(π/4)n, n∈Z
sin3x=-1 x=-π/6+(2/3)πm, m∈z