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mariyatimoshenko
@mariyatimoshenko
August 2022
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Помогите решить уравнение
(9x^2-25) √(x-1)=0
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Lesben
По свойству произведения:
1) 9x^2-25=0
9x^2=25
x^2=25/9
x1=5/3
x2=-5/3
2) sqrt(x-1)=0
x-1=0, но x-1>=0; x>=1
x=1
Ответ: x1=5/3; x2=-5/3; x3=1
1 votes
Thanks 0
AnonimusPro
Verified answer
(9x²-25)√(x-1)=0
(ab=0⇔a=0 ∨ b=0)
1)9x²-25=0, 9x²-5²=0,(3x+5)(3x-5)=0, x1=-5/3, x2=5/3
2)√(x-1)=0, x-1=0, x3=1
2 votes
Thanks 0
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Answers & Comments
1) 9x^2-25=0
9x^2=25
x^2=25/9
x1=5/3
x2=-5/3
2) sqrt(x-1)=0
x-1=0, но x-1>=0; x>=1
x=1
Ответ: x1=5/3; x2=-5/3; x3=1
Verified answer
(9x²-25)√(x-1)=0(ab=0⇔a=0 ∨ b=0)
1)9x²-25=0, 9x²-5²=0,(3x+5)(3x-5)=0, x1=-5/3, x2=5/3
2)√(x-1)=0, x-1=0, x3=1