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HKarisson
@HKarisson
August 2022
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TARTILLO
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3x/(x²-1)=(2x-1)/(x+1)
3x(x+1)=(2x-1)·(x²-1)
3x(x+1)-(2x-1)·(x-1)(x+1)=0
(x+1)[3x-(2x-1)·(x-1)]=0
x1= -1
3x-(2x-1)·(x-1)=0 2x²-6x+1=0 ⇔ x2=(3-√7)/2 x3=(3+√7)/2
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Answers & Comments
Verified answer
3x/(x²-1)=(2x-1)/(x+1)3x(x+1)=(2x-1)·(x²-1)
3x(x+1)-(2x-1)·(x-1)(x+1)=0
(x+1)[3x-(2x-1)·(x-1)]=0
x1= -1
3x-(2x-1)·(x-1)=0 2x²-6x+1=0 ⇔ x2=(3-√7)/2 x3=(3+√7)/2