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superxolodoff
@superxolodoff
August 2022
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Simba2017
Cos(x-pi/2)=sin x
cos2x+sin^2 x=0.75
cos^2 x-sin^2 x+sin^2 x=0.75
cos^2 x=3/4
cosx= +-(корень из 3)/2
cos=+-pi/6+2pi k? где к-целое
в заданном интервале 11pi/6 и 13pi/6
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Answers & Comments
cos2x+sin^2 x=0.75
cos^2 x-sin^2 x+sin^2 x=0.75
cos^2 x=3/4
cosx= +-(корень из 3)/2
cos=+-pi/6+2pi k? где к-целое
в заданном интервале 11pi/6 и 13pi/6