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Ksusha453
@Ksusha453
November 2021
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помогите решить уравненине, алгебра 7 класс
(4х-3)(4х+3)-(х-5)(7х+1)-(3к-5)в квадрате
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leon5807
(16x^2 -9) - (7x^2-35 +x -5) -(9x^2 -30x +25) = 16x^2 -9 -7x^2 -x+5 -9 x^2 +30x -25 =29x-29
если это уравнение, то
29x-29 =0
29(x-1) =0
x-1 =0
x=1
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Ksusha453
спасибо большое)
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Answers & Comments
если это уравнение, то
29x-29 =0
29(x-1) =0
x-1 =0
x=1