Помогите решить второе и третье задание!. Created by KaPuLLIa. matematika-ru

Помогите решить второе и третье задание!...

August 2022 1 4 Report

Помогите решить второе и третье задание!

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njhieyjdf #2.
а) $\frac{3x-1}{ x^{2} }+ \frac{x-9}{3x}= \frac{3(3x-1)}{3 x^{2} }+ \frac{x(x-9)}{3 x^{2} }= \frac{9x-3+ x^{2} -9x}{3 x^{2} }= \frac{ x^{2} -3}{3 x^{2} }$

б) $\frac{1}{2a-b}- \frac{1}{2a+b}= \frac{2a+b-2a+b}{(2a-b)(2a+b)}= \frac{2b}{4 a^{2} - b^{2} }$

в) $\frac{5}{c+3}- \frac{5c-2}{ c^{2}+3 }= \frac{5c-5c+2}{ c(c+3)}= \frac{2}{ c^{2} +3c}$
#3.
$\frac{2a}{a-5} - \frac{5}{a+5}+ \frac{ 2a^{2} }{25- a^{2} }= \frac{2a}{a-5}- \frac{5}{a+5} - \frac{2 a^{2} }{ (a-5)(a+5)}= \frac{2 a^{2}+10a-5a+25- 2a^{2} }{(a-5)(a+5)} =$ $\frac{5a+25}{(a-5)(a+5)}= \frac{5(a+5)}{(a-5)(a+5)}= \frac{5}{a-5}$

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