помогите решить....пожалуйста!!!!!. Created by Daniil2263. algebra-ru

помогите решить....пожалуйста!!!!!...

Daniil2263 @Daniil2263

September 2021 1 11 Report

помогите решить....пожалуйста!!!!!

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sangers1959

Verified answer

(m²+8m-9)/(m²+12m+27)
m²+8m-9=0  D=100     m₁=1   m₂=-9 (m-1)(m+9)=0
m²+12m+27=0  D=36    m₁=-3   m₂=-9 (m+3)(m+9)=0  ⇒
(m-1)(m+9)/((m+3)(m+9))=(m-1)/(m+3).

(2x²+9x-18)/(4x²-9)
2x²+9x-18=0  D=225    x₁=-6 x₂=1,5   2(x+6)(x-1,5)=0
2(x+6)(x-1,5)/((2x-3)(2x+3))=(x+6)(2x-3)/((2x-3)(2x+3))=(x+6)/(2x+3).

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Daniil2263 August 2022 | 0 Ответы

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