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Daniil2263
@Daniil2263
December 2021
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Помогите решить!!!!!ПОЗЯЗЯ
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MizoriesKun
X₁*x₂=6
x₁+x₂=5 ⇒x₁=5-x₂
(5-x₂)*x₂=6
5x₂-x₂²-6=0⇒ x₂²-5x₂+6=0
D=25-24=1
1 x₂=(5+1)/2=3 x₁=5-3=2
2 x₂=(5-1)/2=2 x₁=5-2=3
ответ: (3;2),(2;3)
у=х²+2х-3
х²+2х-3=0
D=4+12=16
x₁=(-2+4)/2=1 (1;0)
х₂=(-2-4)/2=-3 (-3 ;0)
у=-х²+4х+5
D= 16+20=36
x₁=(-4+6)/ -2=-1 (-1;0)
х₂=(-4-6)/ -2=-5 ( 5 ;0)
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Answers & Comments
x₁+x₂=5 ⇒x₁=5-x₂
(5-x₂)*x₂=6
5x₂-x₂²-6=0⇒ x₂²-5x₂+6=0
D=25-24=1
1 x₂=(5+1)/2=3 x₁=5-3=2
2 x₂=(5-1)/2=2 x₁=5-2=3
ответ: (3;2),(2;3)
у=х²+2х-3
х²+2х-3=0
D=4+12=16
x₁=(-2+4)/2=1 (1;0)
х₂=(-2-4)/2=-3 (-3 ;0)
у=-х²+4х+5
D= 16+20=36
x₁=(-4+6)/ -2=-1 (-1;0)
х₂=(-4-6)/ -2=-5 ( 5 ;0)