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Natalya16041980
@Natalya16041980
September 2021
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Помогите с 5 заданием
Производная Функции
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Answers & Comments
а)![f'(x)=(\frac{3}{\sqrt[3]{x}})'-(6\sqrt[3]{x^4})'=\frac{3'*(\sqrt[3]{x})-3(\sqrt[3]{x})'}{(\sqrt[3]{x})^2} -6(\sqrt[3]{x^4})'=-\frac{3(\sqrt[3]{x})'}{x^{2/3}} -6(x^{4/3})'=\frac{-3*\frac1 3*x^{-2/3}}{x^{2/3}} -6*\frac{4}{3}*x^{1/3}=-\frac{1}{\sqrt[3]{x^4}}-8\sqrt[3]{x}](https://tex.z-dn.net/?f=f%27%28x%29%3D%28%5Cfrac%7B3%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%29%27-%286%5Csqrt%5B3%5D%7Bx%5E4%7D%29%27%3D%5Cfrac%7B3%27%2A%28%5Csqrt%5B3%5D%7Bx%7D%29-3%28%5Csqrt%5B3%5D%7Bx%7D%29%27%7D%7B%28%5Csqrt%5B3%5D%7Bx%7D%29%5E2%7D%20-6%28%5Csqrt%5B3%5D%7Bx%5E4%7D%29%27%3D-%5Cfrac%7B3%28%5Csqrt%5B3%5D%7Bx%7D%29%27%7D%7Bx%5E%7B2%2F3%7D%7D%20-6%28x%5E%7B4%2F3%7D%29%27%3D%5Cfrac%7B-3%2A%5Cfrac1%203%2Ax%5E%7B-2%2F3%7D%7D%7Bx%5E%7B2%2F3%7D%7D%20-6%2A%5Cfrac%7B4%7D%7B3%7D%2Ax%5E%7B1%2F3%7D%3D-%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%5E4%7D%7D-8%5Csqrt%5B3%5D%7Bx%7D "f'(x)=(\frac{3}{\sqrt[3]{x}})'-(6\sqrt[3]{x^4})'=\frac{3'*(\sqrt[3]{x})-3(\sqrt[3]{x})'}{(\sqrt[3]{x})^2} -6(\sqrt[3]{x^4})'=-\frac{3(\sqrt[3]{x})'}{x^{2/3}} -6(x^{4/3})'=\frac{-3*\frac1 3*x^{-2/3}}{x^{2/3}} -6*\frac{4}{3}*x^{1/3}=-\frac{1}{\sqrt[3]{x^4}}-8\sqrt[3]{x}")
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