Ответ:
|z|=√(2²+(2√3)²)=4, ф=arctg(2√3/2) =60°, z=4(cos60+sin60*i) -ответ
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Ответ:
|z|=√(2²+(2√3)²)=4, ф=arctg(2√3/2) =60°, z=4(cos60+sin60*i) -ответ