а) =
==sinx-cosx
в) =
==2cosx
б) sin(x-π)*cos(2π+x)/cos(π/2-x)*cos (3π/2-x)
-sin (x)*cos(x)/sin(x)*(-sin(x))
-cos(x)/-sin(x)
ответ ctg(x)
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а) =
==sinx-cosx
в) =
==2cosx
б) sin(x-π)*cos(2π+x)/cos(π/2-x)*cos (3π/2-x)
-sin (x)*cos(x)/sin(x)*(-sin(x))
-cos(x)/-sin(x)
ответ ctg(x)