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Kianna99
@Kianna99
August 2022
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Помогите с номером 5.24 Алгебра 10 класс
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oganesbagoyan
Verified answer
5.24
а)
Loq_3 27 -Loq_√3 27 -Loq_1/3 27 - Loq_√3/2 (64/27) =
Loq_3 3³ -Loq_√3 (√3)⁶ +Loq_3 3³ - Loq_√3/2 (√(4/3) ⁶) =
3 -6 +3 - Loq_√3/2 (√(4/3)⁶) = - Loq_√3/2 (2/√3)⁶) = -(-6)
=6.
-------
б)
Loq_0,4
(
(1/5)*∛50
)
+Loq_0,6
(
√(15) /5
)
+Loq_0,32
(
(2√2)/5
)
=
Loq_0,4
(
∛(50/125)
)
+ Loq_0,6
(
√(15/25)
)
+Loq_0,32
(
√(2²2)/5²)
)
=
Loq_0,4
(
∛(0,4
)
+ Loq_0,6
(
√(0,6)
)
+Loq_0,32
(
√(0,32)
)
=
=1/3 +1/2 +1/2 =1/3+1
= 1 1/3
* * *
4/3
* * *.
-------
в)
(
Loq_1/2 ∛1/4 +6Loq_1/4 1/2 -2Loq_1/16 1/4
)
: Loq_√2 8^(1/5) =
(
Loq_1/2 (1/2)^(2/3) +6Loq_1/4 √(1/4) -2Loq_1/16 √(1/16)
) :
Loq_(2)^(1/2) 2^(3/5) =
(
2/3 +6*(1/2) -2*(1/2)
) :
(3/5) /(1/2) = (8/3)*(5/6)
=20/9.
**************
Удачи !
1 votes
Thanks 1
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Answers & Comments
Verified answer
5.24а) Loq_3 27 -Loq_√3 27 -Loq_1/3 27 - Loq_√3/2 (64/27) =
Loq_3 3³ -Loq_√3 (√3)⁶ +Loq_3 3³ - Loq_√3/2 (√(4/3) ⁶) =
3 -6 +3 - Loq_√3/2 (√(4/3)⁶) = - Loq_√3/2 (2/√3)⁶) = -(-6) =6.
-------
б) Loq_0,4 ((1/5)*∛50 ) +Loq_0,6 (√(15) /5) +Loq_0,32 ((2√2)/5)=
Loq_0,4 ( ∛(50/125)) + Loq_0,6 (√(15/25)) +Loq_0,32 (√(2²2)/5²) )=
Loq_0,4 ( ∛(0,4) + Loq_0,6 (√(0,6)) +Loq_0,32 (√(0,32) ) =
=1/3 +1/2 +1/2 =1/3+1 = 1 1/3 * * * 4/3 * * *.
-------
в) (Loq_1/2 ∛1/4 +6Loq_1/4 1/2 -2Loq_1/16 1/4 ): Loq_√2 8^(1/5) =
(Loq_1/2 (1/2)^(2/3) +6Loq_1/4 √(1/4) -2Loq_1/16 √(1/16) ) : Loq_(2)^(1/2) 2^(3/5) = (2/3 +6*(1/2) -2*(1/2) ) :(3/5) /(1/2) = (8/3)*(5/6)=20/9.
**************
Удачи !