Ответ:

• a) y = 4x³ =4×3=13+3=16x

Используемые правила:

1) (xⁿ)' = nxⁿ⁻¹

2) (x + y)' = x' + y'

3) (const)' = 0

4) (u/v)' = (u'v - uv')/v²

а) y = 4x³ => y' = 3*4 *x³⁻¹ = 12x²

б) y = x² + 5 => y' = (x²)' + 5' = 2x + 0 = 2x

в) y = x²(2x + 8) => y' = 2x³ + 8x² = (2x³)' + (8x²)' = 6x² + 16x = 2x(3x² + 8)

г) ↓


д) y = 4x³ - 3x² - x - 1 => y' = (4x³)' - (3x²)' - (x)' - (1)' = 12x² - 6x - 1

x₀ = -1

=> y(x₀) = 12*(-1)² - 6*(-1) - 1 = 12 + 6 - 1 = 17