помогите с решением пазязя). Created by kirusha2001151. algebra-ru

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kirusha2001151 @kirusha2001151

May 2021 1 14 Report

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ndusha

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$\frac{2x}{x^2-4} - \frac{2}{x^2-4}:( \frac{x+1}{2x-2}- \frac{1}{x-1} ) = \frac{2x}{x^2-4} - \frac{2}{x^2-4}:( \frac{x+1}{2(x-1)}- \frac{2}{2(x-1)} ) = \\ \frac{2x}{x^2-4} - \frac{2}{x^2-4}: \frac{x+1-2}{2(x-1)} =\frac{2x}{x^2-4} - \frac{2}{x^2-4}: \frac{x-1}{2(x-1)} = \\ \frac{2x}{x^2-4} - \frac{2}{x^2-4}: \frac{1}{2} = \frac{2x}{x^2-4} - \frac{2}{x^2-4}*2 =\frac{2x}{x^2-4} - \frac{4}{x^2-4} = \\ \frac{2x-4}{x^2-4} = \frac{2(x-2)}{(x-2)(x+2)} = \frac{2}{x+2} \\ \\ x=1/2$
$\frac{2}{1/2+2} =2/2.5=20/25=4/5=0.8$

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