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kutsenckosofia
@kutsenckosofia
July 2022
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sedinalana
Verified answer
1)0,5(b-3)/[0,5(b²-3b+9) -(2b-6)/[1/3*(b³+27)]=
=(b-3)/(b²-3b+9)-3(2b-6)/[(b+3)(b²-3b+9)]=(b²-9-6b+18)/(b³+27)=(b-3)²/(b³+27)
2
(b-3)²/(b³+27)*0,8(b³+27)/(b-3)=0,8(b-3)=4/5(b-3)=(4b-12)/5
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Answers & Comments
Verified answer
1)0,5(b-3)/[0,5(b²-3b+9) -(2b-6)/[1/3*(b³+27)]==(b-3)/(b²-3b+9)-3(2b-6)/[(b+3)(b²-3b+9)]=(b²-9-6b+18)/(b³+27)=(b-3)²/(b³+27)
2
(b-3)²/(b³+27)*0,8(b³+27)/(b-3)=0,8(b-3)=4/5(b-3)=(4b-12)/5