помогите с тригонометрией. Created by vbulay92. algebra-ru

2sin170=2sin(180-10)=2sin10cos40=sin501) 2sin10+sin50=sin10+sin10+sin50=sin10+2*sin*cos =sin10+2*sin30*cos20=sin10+cos20= sin10+sin70=2*sin*cos = 2*sin40*cos302) cos130=cos(90+40)=-sin403)

помогите с тригонометрией...

vbulay92 @vbulay92

July 2022 1 5 Report

помогите с тригонометрией

Answers & Comments

MrSoys 2sin170=2sin(180-10)=2sin10
cos40=sin50
1) 2sin10+sin50=sin10+sin10+sin50=sin10+2*sin $\frac{50+10}{2}$ *cos $\frac{50-10}{2}$ =sin10+2*sin30*cos20=sin10+cos20= sin10+sin70=2*sin $\frac{70+10}{2}$ *cos $\frac{70-10}{2}$ = 2*sin40*cos30
2) cos130=cos(90+40)=-sin40
3) $\frac{2* \frac{ \sqrt{3} }{2}*sin40 }{-sin40} = -2* \frac{ \sqrt{3} }{2} = - \sqrt{3}$

6 votes Thanks 5

vbulay92 можешь расписть, как это получил(а) cos40=sin50?

MrSoys cos40=cos(90-50)=sin50

Answers & Comments

pomogite reshit uravneniea67b6ba2afecc2d73c5b4348cbdae07a 92697

pomogite s arifmeticheskoj progressiej6d3be74023987d65b6da22b4c5accb35 66196

reshite 65 i 66 nomera s pomoshyu zameny 50 ballov

pomogite reshit neravenstvo s modulem chem skoree tem luchshe

chetyre lampy rasschitannye na napryazhenie u 120 v i silu toka i 050 a kazhdaya

mezhdu klemmoj a i dvizhkom s potenciometra av imeyushego soprotivlenie 120 om pod

chto oboznachaet etot znachokd011963359c2e406e23b1d2bccb1dafa 49678

dve pryamye peresekayas obrazuyut chetyre ugla izvestno chto summa dvuh vertikal

reshite zadachu po fizike a to ya nichego ne ponimayu

raspredelit varianty otvetov po kolonkamne vse varianty dolzhny byt vneseny v

рекомендуемые вопросы

Helpful Links

Helpful Social