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alekskholod01
@alekskholod01
June 2022
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помогите с заданием
найдите площадь фигуры,ограниченной линиями
у=-х^2+9,y=0
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sangers1959
Verified answer
Y=-x²+9 y=0
-x²+9=0
x²=9
x₁=-3 x₂=3 ⇒
S=₋₃∫³(-x²+9)dx=(-x³/3+9x-0) ₋₃|³=-3³/3+9*3-(-(-3)³/3+9*(-3))=
=-9+27-(9-27)=18-(-18)=18+18=36.
Ответ: S=36 кв. ед.
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Answers & Comments
Verified answer
Y=-x²+9 y=0-x²+9=0
x²=9
x₁=-3 x₂=3 ⇒
S=₋₃∫³(-x²+9)dx=(-x³/3+9x-0) ₋₃|³=-3³/3+9*3-(-(-3)³/3+9*(-3))=
=-9+27-(9-27)=18-(-18)=18+18=36.
Ответ: S=36 кв. ед.